Limits — Greg School

Gregory Leal

Proof of the Theorem: \(\lim_{ϴ→0}\frac{sinϴ}{ϴ}=1\)

Proof of the Theorem: \(\lim_{ϴ→0}\frac{sinϴ}{ϴ}=1\)

In this lesson, we’ll prove that \(\lim_{ϴ→0}\frac{sinϴ}{ϴ}=1\). We'll prove this result by using the squeeze theorem and basic geometry, algebra, and trigonometry. In a future lesson, we'll learn why this result is important: the reason being because knowledge that \(\lim_{ϴ→0}\frac{sinϴ}{ϴ}=1\) is required to find the derivatives of the sin and cosine functions. But we'll save that for a future lesson.